I with integration using partial fractions

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SUMMARY

The integral of the function (1-x^2)/(x^3+x) can be computed using partial fraction decomposition. The correct decomposition is (1-x^2)/(x(1+x^2)) = A/x + (B + Cx)/(1+x^2). The coefficients A, B, and C must be determined by equating coefficients from both sides of the equation. The initial attempt incorrectly omitted the linear term in the denominator, leading to an incomplete solution.

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  • Understanding of integral calculus
  • Familiarity with partial fraction decomposition
  • Knowledge of polynomial equations and coefficient comparison
  • Basic algebraic manipulation skills
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  • Study the method of partial fraction decomposition in detail
  • Practice solving integrals involving rational functions
  • Learn about polynomial long division for improper fractions
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Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of partial fraction decomposition in action.

farisallil
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Homework Statement



Compute the integral:
int ((1-x^2)/(x^3+x)) dx



Homework Equations


int ((1-x^2)/(x^3+x)) dx


The Attempt at a Solution


I think I should use the partial fraction method to simplify the fraction
so
(1-x^2)/(x^3+x)= A/x + B/ (1+x^2)
Therefore
A(1+x^2)+B(x)=1-x^2
putting it in a polynomial form:
x^2 (A)+x (B) + 1 (A)= 1- x^2
and by equating the coefficients,
A = -1
B = 0
However, A doesn't satisfy the constant on the LHS (+1)

So what is the thing that I did wrong??

Thanks in advance
 
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I think you missed the quadratic part of your partial fraction decomposition, it should be

[tex]\frac{1-x^2}{x(1+x^2)}= \frac{A}{x}+\frac{B+Cx}{1+x^2}[/tex]
 

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