I with Radial Acceleration -it is an easy one

AI Thread Summary
The discussion revolves around calculating the centripetal acceleration of an airplane's propeller, given a rotation period of 3 milliseconds and a linear speed of 3000 m/s. Initial calculations led to a radius of approximately 1.432 meters and a centripetal acceleration of 6.28 m/s². However, a mistake in the decimal placement was identified, suggesting the correct acceleration should be 6284916 m/s². Participants emphasized the importance of showing work for clarity and accuracy in problem-solving. The thread concludes with encouragement to recheck calculations for precision.
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The period of the rotation of an airplanes ellipse is T=3 milliseconds,linear speed in the top is 3*10^3 m/s.What's the centripetal(radial) acceleration of the top?I need a step by step guide it would be really helpful.Thanks.
 
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Work?
 
If I knew what an 'airplane ellipse' is, I could probably help you.
 
Sorry I meant an airplanes propeller.
 
As physicsvalk kindly stated, show your previous working or attempts, we're here to help, not do it for you.
 
Ok I did it.

v=3000 m/s
T=0.003s

v=s/t 3000m/s = s / 0.003s s=vt s=3000m/s * 0.003s s=9m

s=2piR 9m=2*3.14*R r=9m/6.28 r=1.432m

a=v^2/r a=(3000m/s)^2 / 1.432m = 6.284916m/s^2
 
Yep, you got the same answer as I did. Your working is a little difficult to follow though.
 
Woops, no wait. Its wrong, because I made the same mistake you did. Its an order of magnitude mistake. (The numbers are right, but the decimal place is wrong).

Maybe try again? I think you will get it right second time, since it is only the decimal place that is wrong, you must have been close, but maybe made a silly error?
 
In fact, I think it is just on the last line where you went wrong.
 
  • #10
yes it should have been 6284916m/s^2.Thanks to all for helping
 
  • #11
yep, no worries
 
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