- #1
Townsend
- 232
- 0
I just need to make sure I understand how to do this and that I am doing everything correctly. Could someone check my work please?
You place the spring vertically with one end on the floor. You then drop a 1.70 kg book onto it from a height of 0.70 m above the top of the spring. Find the maximum distance the spring will be compressed.
So
k_1 + U_1 + W_{other} = k_2 + U_2
I have that
k_1=0, U_1= mgy_1, W_o=0, k_2=0, U_2=1/2kx^2
So the issue is that I have to the potential energy to the start of the spring plus the distance the spring compresses.
To solve this I need to adjust the equations to look like
mg(y+x)=1/2kx^2
This works out to a homogenous quadradic that looks like
1/2kx^2-mgx-mgy=0
Plugining in values and solving gets me
0.142 meters.
TIA
T
You place the spring vertically with one end on the floor. You then drop a 1.70 kg book onto it from a height of 0.70 m above the top of the spring. Find the maximum distance the spring will be compressed.
So
k_1 + U_1 + W_{other} = k_2 + U_2
I have that
k_1=0, U_1= mgy_1, W_o=0, k_2=0, U_2=1/2kx^2
So the issue is that I have to the potential energy to the start of the spring plus the distance the spring compresses.
To solve this I need to adjust the equations to look like
mg(y+x)=1/2kx^2
This works out to a homogenous quadradic that looks like
1/2kx^2-mgx-mgy=0
Plugining in values and solving gets me
0.142 meters.
TIA
T