Ice Cube Pressure on Incline: Solve for F

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To determine the pressure exerted by the ice cube on the incline, the force acting on the cube must first be calculated. The force can be derived from the mass of the cube, which is found using its density and volume, leading to F = ma, where 'a' is the acceleration down the incline. The pressure is then calculated using the formula P = F / A, where A is the area of contact, which is the base area of the cube. The challenge lies in identifying the correct components of the gravitational force acting on the cube, specifically the perpendicular force relative to the incline. Understanding these forces is crucial for accurately calculating the pressure exerted by the ice cube.
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An ice cube, p = 917 kg/m^3, is sliding down a 16 degree frictionless incline. The sides of the cube each have a length of .75 m. What pressure does the cube exert on the incline?

P = F / A
= F / .75^3
= F / .42


F = ma
= 917 * a

I am having a problem figuring out the Force for this equation. I know it's simple, just can't put my finger on it. Please help.
 
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Which force is acting on the cube? One component of that force is in the direction of the motion of the cube, and one is perpendicular to the contact surface (m^2 !) of the cube and the incline.
 

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