Solving PV=nRT: Finding Volume

In summary, the conversation discusses the calculation of the volume of an ideal gas using the formula PV = nRT, with the given values of n = 5.3 moles, R = 8.31 J/(mol K), and T = 273 K. There is a discussion about the appropriate pressure unit to use, with the conclusion that for everyday use, atm is more commonly used while in SI units, Pa is used. The final calculated volume is determined to be 118.64 liters, which is deemed to be large for a bottle.
  • #1
goonking
434
3

Homework Statement


upload_2015-5-15_0-53-46.png


Homework Equations


PV = nRT

The Attempt at a Solution


n = 5.3 moles
R = 8.31 J/(mol K)
T = 273 K
now, with P, do we use 1 atm or 1.013 x 105

i'll go with the latter, and the answer comes out to be 0.119 liters , does this sound correct?
 
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  • #2
goonking said:

Homework Statement


View attachment 83502

Homework Equations


PV = nRT

The Attempt at a Solution


n = 5.3 moles
R = 8.31 J/(mol K)
T = 273 K
now, with P, do we use 1 atm or 1.013 x 105

i'll go with the latter, and the answer comes out to be 0.119 liters , does this sound correct?
What is R in terms of liter-atm/mol K ?
 
  • #3
Raghav Gupta said:
What is R in terms of liter-atm/mol K ?
hmm, it is 0.082

also, do we normally express P in Pascals or atm?
 
  • #4
goonking said:
hmm, it is 0.082

also, do we normally express P in Pascals or atm?
In SI units it is Pa but normally it is a very small unit.
In our day to day life we use atm.
Remember if you are solving you should keep a track on units.
Your attempt is also good.
You will get answer in m3 and then 1m3 = 1000 liter.
 
  • #5
Raghav Gupta said:
In SI units it is Pa but normally it is a very small unit.
In our day to day life we use atm.
Remember if you are solving you should keep a track on units.
Your attempt is also good.
You will get answer in m3 and then 1m3 = 1000 liter.
hmmm, is 1.19 L correct?
 
  • #6
goonking said:
hmmm, is 1.19 L correct?
No, can you show what have you done?
 
  • #7
Raghav Gupta said:
No, can you show what have you done?

P V = n R T
(1.013x105) V = (5.3 moles )( 0.082 liter-atm/mol K) (273K)

V = 0.00119 , I'm pretty sure this is in liters
 
  • #8
goonking said:
P V = n R T
(1.013x105) V = (5.3 moles )( 0.082 liter-atm/mol K) (273K)

V = 0.00119 , I'm pretty sure this is in liters
But P should be in atm then.
I said keep track of units.
So take P = 1atm.
 
  • #9
Raghav Gupta said:
But P should be in atm then.
I said keep track of units.
So take P = 1atm.
so V = (5.3 moles )( 0.082 liter-atm/mol K) (273K) = 118.64 Liters?

thats huge for a bottle
 
  • #10
goonking said:
so V = (5.3 moles )( 0.082 liter-atm/mol K) (273K) = 118.64 Liters?

thats huge for a bottle
Yeah, that was what I was getting.

Yeah, that is huge for a bottle but holding 5.3 moles of an ideal gas is a big thing.
 
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1. How do I solve for volume in the ideal gas law equation PV=nRT?

To solve for volume in the ideal gas law equation, you will need to rearrange the equation to solve for V. This can be done by dividing both sides of the equation by P and multiplying both sides by RT. The resulting equation will be V=nRT/P.

2. What units should be used when solving for volume in the ideal gas law equation?

The units for volume in the ideal gas law equation are typically expressed in liters (L) or cubic meters (m^3). It is important to use the same units for all variables in the equation to ensure accurate results.

3. Can the ideal gas law equation be used to solve for volume at non-standard conditions?

Yes, the ideal gas law equation can be used to solve for volume at non-standard conditions, as long as the other variables (pressure, moles, and temperature) are known. However, it is important to note that the ideal gas law is based on certain assumptions and may not accurately predict the behavior of real gases at extreme conditions.

4. How does changing the temperature or pressure affect the volume in the ideal gas law equation?

In the ideal gas law, an increase in temperature will result in an increase in volume, while an increase in pressure will result in a decrease in volume. This is because temperature and pressure have a direct relationship with volume, meaning that as one variable increases, the other will also increase or decrease.

5. What are some real-life applications of using the ideal gas law to solve for volume?

The ideal gas law is commonly used in various fields of science and engineering, such as chemistry, physics, and thermodynamics. It is used to predict the behavior of gases in different conditions and is applied in industries such as manufacturing, energy production, and environmental science. Some specific examples include calculating the volume of a gas inside a container, determining the amount of gas needed for a chemical reaction, and analyzing the behavior of gases in a combustion engine.

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