# Homework Help: Ideal gas law

1. May 15, 2015

### goonking

1. The problem statement, all variables and given/known data

2. Relevant equations
PV = nRT

3. The attempt at a solution
n = 5.3 moles
R = 8.31 J/(mol K)
T = 273 K
now, with P, do we use 1 atm or 1.013 x 105

i'll go with the latter, and the answer comes out to be 0.119 liters , does this sound correct?

2. May 15, 2015

### Raghav Gupta

What is R in terms of liter-atm/mol K ?

3. May 15, 2015

### goonking

hmm, it is 0.082

also, do we normally express P in Pascals or atm?

4. May 15, 2015

### Raghav Gupta

In SI units it is Pa but normally it is a very small unit.
In our day to day life we use atm.
Remember if you are solving you should keep a track on units.
You will get answer in m3 and then 1m3 = 1000 liter.

5. May 15, 2015

### goonking

hmmm, is 1.19 L correct?

6. May 15, 2015

### Raghav Gupta

No, can you show what have you done?

7. May 15, 2015

### goonking

P V = n R T
(1.013x105) V = (5.3 moles )( 0.082 liter-atm/mol K) (273K)

V = 0.00119 , i'm pretty sure this is in liters

8. May 15, 2015

### Raghav Gupta

But P should be in atm then.
I said keep track of units.
So take P = 1atm.

9. May 15, 2015

### goonking

so V = (5.3 moles )( 0.082 liter-atm/mol K) (273K) = 118.64 Liters?

thats huge for a bottle

10. May 15, 2015

### Raghav Gupta

Yeah, that was what I was getting.

Yeah, that is huge for a bottle but holding 5.3 moles of an ideal gas is a big thing.