1. The problem statement, all variables and given/known data
Air that initially occupies 0.140m^{3} (V_{1}) at a gauge pressure of 103.0 kPa (p_{1}) is expanded isothermally to a pressure of 101.3 kPa (p_{2}) and then cooled at constant pressure until it reaches its initial volume. Compute the work done by the air.

3. The attempt at a solution
We can find V_{2} easily enough by multiplying p_{1} and V_{1} and dividing by p_{2} because both p_{1}V_{1} and p_{2}V_{2} equal nRT. I can now fill in most of the formula:

Here, I thought I could then just back substitute nRT for either p_{1}V_{1} or p_{2}V_{2} and I'd be golden but the answer I'm getting is different from the back of the book (5.6 kJ). I'm getting .001 kJ with plugging these in:

They may be pulling a sneaky one on you. Only the first pressure given is specified as gauge pressure. Treat the second pressure as actual pressure. (That would make this a much more realistic problem!)

That was it! Man, it feels like this is a reading comprehension problem more than an actual physics problem. I was really worried that I wasn't understanding something very fundamental about pressures, temperatures and volumes.