- #1
ehrenfest
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Homework Statement
The following is a probability density distribution for an ideal gas:
[tex] p(v_x,v_y,v_z) = (2 \pi \sigma ^2)^{-3/2} \exp\left({\frac{v_x^2 +v_y^2+v_z^2}{2 \sigma^2}}\right) [/tex]
[tex]E = 0.5 m |\vec{v}|^2[/tex]
Find p(E).
Homework Equations
The Attempt at a Solution
I want to just plug in what E but that gives the wrong answer and I cannot figure out why.
[tex] p(E) = (2 \pi \sigma ^2)^{-3/2} \exp\left({\frac{E}{m \sigma^2}}\right) [/tex]
Why is that wrong? It makes no sense, but I just plugged in what E was! This is really bothering me.