(I):(adsbygoogle = window.adsbygoogle || []).push({});

dU=dW+dQ

also (II):

[tex]dU=\frac{3}{2}RdT[/tex]

if you compress a gas dW in dU is positive from pV=nRT lesser volume could either mean more pressure or more T. If dV gives dp only then dT=0 how can then dU for dW in (I) be equal dU in (II)?

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# Ideal gases and U

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