Ideal op amp (current to voltage converter + inverting)

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SUMMARY

The discussion focuses on deriving an expression for the output voltage (Vo) in relation to the input current (Iin) in an ideal operational amplifier (op amp) circuit configured as a current-to-voltage converter. The user initially attempts to include the load resistor (RL) in their derivation but is advised that as long as the second op amp's output can drive RL, it does not need to be included in the gain equation. The key equations discussed are V1 = -IinRf and Vo = -R2/R1(-IinRf), emphasizing the importance of checking the op amp's output current capability against the expected voltage swing.

PREREQUISITES
  • Understanding of operational amplifier configurations
  • Familiarity with current-to-voltage conversion principles
  • Knowledge of gain equations in op amp circuits
  • Basic circuit analysis skills
NEXT STEPS
  • Study the output current capability of operational amplifiers
  • Learn about the impact of load resistors on op amp performance
  • Explore advanced op amp configurations for signal processing
  • Investigate the effects of voltage swing limitations in op amp circuits
USEFUL FOR

Electrical engineers, students studying circuit design, and anyone involved in designing or analyzing operational amplifier circuits will benefit from this discussion.

naspek
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Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL[/size]
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg
 
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naspek said:

Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL[/size]
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg

Good question. As long as the 2nd opamp's output is capable of driving RL, you don't need to include it in the gain equation. In real life, you would check the output current capability of the opamp, figure out the voltage swing based on your gain equation (for whatever values of Iin you expect), and make sure you weren't exceeding that output current rating.
 

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