Ideal op amp (current to voltage converter + inverting)

  • Thread starter naspek
  • Start date
  • #1
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Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg
 

Answers and Replies

  • #2
berkeman
Mentor
59,471
9,596

Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg

Good question. As long as the 2nd opamp's output is capable of driving RL, you don't need to include it in the gain equation. In real life, you would check the output current capability of the opamp, figure out the voltage swing based on your gain equation (for whatever values of Iin you expect), and make sure you weren't exceeding that output current rating.
 

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