- #1
Dustinsfl
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An nxn matrix A is said to be idempotent if [tex]A^2=A[/tex]. Show that if [tex]\lambda[/tex] is an eigenvalue of an idempotent matrix, then [tex]\lambda[/tex] must be 0 or 1.
The only reason I can think of is that it must 0 or 1 because if you square the values 0 and 1 don't change.
The only reason I can think of is that it must 0 or 1 because if you square the values 0 and 1 don't change.