Identical spin 1/2 particles in a box.

Click For Summary
SUMMARY

The discussion focuses on the quantum mechanics of two identical spin 1/2 particles confined in a cubic box of side L. The energy of the system is derived using the formula E = (ħ²π²)/(2mL²)(n_x² + n_y² + n_z²), where n_x, n_y, and n_z are quantum numbers. The wave function is expressed as ψ(x,y,z) = √(8/L³) sin((n_xπx)/L)sin((n_yπy)/L)sin((n_zπz)/L). The participants emphasize the necessity of constructing an antisymmetric wave function to comply with the indistinguishability of identical fermions.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the Schrödinger equation.
  • Familiarity with the concept of spin and antisymmetry in wave functions.
  • Knowledge of quantum numbers and their significance in particle confinement.
  • Basic grasp of the principles of identical particles in quantum systems.
NEXT STEPS
  • Study the derivation of antisymmetric wave functions for identical fermions.
  • Learn about the implications of the Pauli exclusion principle on particle systems.
  • Explore the mathematical techniques for solving the Schrödinger equation in three dimensions.
  • Investigate the role of quantum numbers in determining energy levels in confined systems.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on particle physics, wave functions, and the behavior of identical fermions in confined spaces.

phyky
Messages
57
Reaction score
0

Homework Statement


two identical particles of spin 1/2 that confined in a cubical box of side L. find the energy and wave function (non-interacting between particles)


Homework Equations


for a cubic boxby and reducing the Schrödinger equation:
ψ(x,y,z)=√(8/L3 ) sin((nx πx)/L)sin((ny πy)/L)sin((nz πz)/L)
E= (ħ2 π2)/(2mL2 ) (nx2+ny2+nz2 )

The Attempt at a Solution



E=ε12=(ħ2 π2)/(2mL2 ) [(n_x12+n_y12+n_z12 )+(n_x22+n_y22+n_z22 ) ]
n how about the wave function? should i find it anti-symmetry wave funtion?
ψa(r1,r2;S1,S2)=ψs(r1,r2)χa(S1,S2)
a(r1,r2)χs(S1,S2)
then the wave function is combination of this?
 
Last edited:
Physics news on Phys.org
phyky said:
ψa(r1,r2;S1,S2)=ψs(r1,r2)χa(S1,S2)
a(r1,r2)χs(S1,S2)
then the wave function is combination of this?
I think you have the basic idea. You need to find the combinations that result in an antisymmetric wave function. If you meant to say that ψs(r1,r2)χa(S1,S2)=ψa(r1,r2)χs(S1,S2), however, that's obviously wrong.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 9 ·
Replies
9
Views
7K
Replies
17
Views
5K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K