Identify Bottles: Lead Nitrate, HCl, Copper Sulfate, Sodium Carbonate

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The discussion focuses on identifying four chemical substances based on their reactions. Bottle 1 is confirmed as lead nitrate, Bottle 2 as hydrochloric acid, Bottle 3 as sodium carbonate, and Bottle 4 as copper sulfate. The reactions between these substances produce specific precipitates or gases, with sodium carbonate reacting with hydrochloric acid to produce carbon dioxide. The participants clarify that hydrogen gas does not evolve when HCl is added to lead nitrate or copper sulfate, as carbon dioxide and water are the products instead. Overall, the identification and reactions discussed are deemed correct.
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Homework Statement



Screen Shot 2016-07-01 at 3.53.00 PM.png


Identify the bottles

2. Homework Equations

The Attempt at a Solution



Bottle 1 is lead nitrate as lead is the only metal that will form a precipitate with the other anions.

Bottle 3+4 = copper sulfate + sodium carbonate -- because it produces blue precipitate

Bottle 2+3 = hydrochloric acid + sodium carbonate -- as acid + metal = salt + hydrogen gas.

This means sodium carbonate is bottle 3, hydrochloric acid is bottle 2, and copper sulfate is bottle 4. Can someone check this?

If this is correct, out of interest, why doesn't hydrogen gas evolve when HCl is added to lead nitrate and copper(II) sulfate?

Cheers!
 
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2+3 : Sodium carbonate is not a metal and the gas is not hydrogen.
That should also explain why HCl does not produce a gas with PbNO3 or CuSO4
 
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I see, I forgot. CO2 and water are evolved, not H2! Other than that, is the rest of the answers correct?

Cheers!
 
If I have deduced correctly from your statements, you are saying;
1 - PbNO3
2 -HCl
3- Na2CO3
4 - CuSO4

So that means;
1 & 2 is lead nitrate + HCl -> white precipitate of
1 & 3 is lead nitrate + sodium carbonate -> white precipitate of
1 & 4 is lead nitrate + copper sulphate -> white precipitate of
2 & 3 is HCl + sodium carbonate -> gas produced = CO2
2 & 4 is HCl + copper sulphate -> no visible reaction
3 & 4 is sodium carbonate + copper sulphate -> blue precipitate of
all plausible, so you are correct.
You could write out the equations for each, apart from the no reaction, if you wanted to make clear what was happening.
 
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I see, cheers!
 
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