Identifying Parametric Equations from Graphs

Click For Summary
SUMMARY

This discussion focuses on identifying parametric equations from given graphs, specifically analyzing graphs labeled 1 through 3. The participant concludes that graphs 1 and 3 are not periodic and are excluded from being simple trigonometric functions due to their overall increase in both x and y. The equations for graphs E and F are derived as x = -2sin(t), y = -2cos(t) and x = sin(3t), y = sin(4t), respectively, which helps in matching them to the corresponding graphs. The discussion emphasizes the importance of recognizing symmetry and periodicity in graph analysis.

PREREQUISITES
  • Understanding of parametric equations
  • Familiarity with trigonometric functions
  • Knowledge of graph symmetry
  • Ability to analyze periodicity in functions
NEXT STEPS
  • Study the properties of parametric equations in detail
  • Learn how to identify symmetry in graphs
  • Explore the concept of periodic functions and their characteristics
  • Practice matching parametric equations to their graphical representations
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in graphing parametric equations and understanding their properties.

Slimsta
Messages
189
Reaction score
0

Homework Statement


http://img704.imageshack.us/img704/5760/pqg.jpg


Homework Equations





The Attempt at a Solution


So i know that graph 2 is C
also i know that A and G can't be any of those because its a circular shape..

the rest i have no idea how to do in order to get those crazy graphs
 
Last edited by a moderator:
Physics news on Phys.org
1 and 3 are clearly not periodic- x and y both have an overall increase. That tells you that they are not simply trig functions and that excludes A, B, C, and G. They do appear to have a symmetry about the line y+ x= some number. D is not symmetric so that's excluded leaving only E and F which, because of the "t" added increase steadily as t increases. Subtracting off that "t" is the same as rotating the x= y= t line to the x-axis:
E then becomes x= -2sin(t) and y= -2cos(t) while F becomes x= sin(3t) and y= sin(4t). It should be easy to see which of those 1 and 3 correspond to.
 
HallsofIvy said:
1 and 3 are clearly not periodic- x and y both have an overall increase. That tells you that they are not simply trig functions and that excludes A, B, C, and G. They do appear to have a symmetry about the line y+ x= some number. D is not symmetric so that's excluded leaving only E and F which, because of the "t" added increase steadily as t increases. Subtracting off that "t" is the same as rotating the x= y= t line to the x-axis:
E then becomes x= -2sin(t) and y= -2cos(t) while F becomes x= sin(3t) and y= sin(4t). It should be easy to see which of those 1 and 3 correspond to.

so all you did is just taking the t's out of it??! that makes sense..
one thing i don't really get is how you match it to the graph..
i mean, i could guess because i had 50/50 but my point is to understand it.. because what if i have like 20 graphs to match :/
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K