If given the capacitance in (pF), how do you find the electric field (V/m)?

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To find the electric field (V/m) given capacitance in picofarads (pF), the relevant equation involves the potential difference across a capacitor, which is calculated as QC, where Q is the charge and C is the capacitance. The electric field strength between the plates is determined by the formula QC/d, with d representing the distance between the plates. It is important to note that capacitance and electric field are distinct concepts, making the term "conversion factor" inappropriate in this context. Understanding the relationship between these variables is crucial for accurate calculations. The discussion emphasizes the need for clarity in terminology when addressing electrical concepts.
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What is the equation or conversion factor?
 
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The potential difference across a capacitor will be QC, where Q is the charge and
C the capacitance, and then the field strength between the plates will be QC/d, where
d is the distance between the plates
 
thebest140 said:
What is the equation or conversion factor?

Since capacitance and electric field are two different things then "conversion factor" is not really the right term to use. It's a bit like asking what is the conversion factor between mass in micrograms and speed.
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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