If integral equal to zero, then?

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Homework Statement


if this statement is true:
\int_0^\infty f(x) dx= 0
then is this true?
f(x) = 0 in domain x\in [0,\infty)


Homework Equations


-NA-


The Attempt at a Solution


Hmm.. I can't come out with a formula that refute that. I would think of an odd function that changes sign in \infty/2, except it doesn't exist.

I would think it's false, but i need some example...
 
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What if f(x) = sin(x)?
 
SteamKing said:
What if f(x) = sin(x)?

Its improper integral is not defined.

ehild
 
-deleted: multiple post-
 
actually I think it might be er..
f(x)=sin(x) for x=[0,2\pi]
f(x)=0 for others
 
That will do ...

ehild
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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