If the atmospheric pressure is 0.975 atm

AI Thread Summary
To determine the pressure of the enclosed gas in an open-tube manometer with an atmospheric pressure of 0.975 atm and a height difference of 52 cm, a proportion can be set up using the conversion factor of 760 torr for 1 atm. The calculation yields a pressure of 741 torr for the gas. However, the density of the gas may also be relevant for further calculations. The height difference in the manometer must be considered to accurately assess the gas pressure. Understanding these principles is essential for solving the problem correctly.
priscilla89
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Homework Statement



If the atmospheric pressure is 0.975 atm, what is the pressure of the enclosed gas when its an open-tube manometer and the h is 52 cm?

The Attempt at a Solution



I know you would have to set up a proportion. I was thinking

.975 / 1 = x / 760

x = 741 torr

But you will need the density of this gas, right?
 
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priscilla89 said:

Homework Statement



If the atmospheric pressure is 0.975 atm, what is the pressure of the enclosed gas when its an open-tube manometer and the h is 52 cm?

The Attempt at a Solution



I know you would have to set up a proportion. I was thinking

.975 / 1 = x / 760

x = 741 torr

But you will need the density of this gas, right? I know we'll have to use the height but I don't know how.

This question is at this website below, its on pg 399 Q 15 i. I will appreciate the help for just one question at least.

http://www.chemistry.ohio-state.edu/~rzellmer/chem122/homewk/homewk9/122ch10_exer9.pdf"
 
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