Ratch
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sophiecentaur,
A consensus does not determine the truth. Reason and facts do. Everyone I discussed this with cannot refute me, yet they prefer to "go with the flow" even though they know it is descriptively wrong. As is "current flow" also wrong.
Yes, agreed. Let's see where this takes us.
I thought I made it clear in post #48 where I said "A battery's voltage is because of valance electron displacement of its two metal terminals due to chemical reaction, and not electron crowding and separation due to a dielectric as in a capacitor." So no, it is not the same in both cases.
The DC generator has no dielectric, therefore, its voltage will be only by EM induction as you stated, and not by charge separation and crowding or spacing out of electrons.
I agree with the above.
A floating cap is a topology, not a verb. It means that one of it terminals is left "floating", i.e. it is not connected to anything.
The OP asked for a qualitative explanation, not a quantative one.
I was answering your previous statement where you said "with no current flowing, Inductance is hardly relevant."
I answered "And in the final state of things, with no voltage changing, neither is capacitance." So in the proper context, you should have interpretated it as I saying capacitance is not relevant if voltage is not changing. You instead interpreted it as I as saying that capacitance changed.
Ratch
But no reference or even a quote with your personal terminology being used elsewhere? That's hardly PF style for asserting "truth".
A consensus does not determine the truth. Reason and facts do. Everyone I discussed this with cannot refute me, yet they prefer to "go with the flow" even though they know it is descriptively wrong. As is "current flow" also wrong.
But the chemical reaction in a battery doesn't continue all the time. It stops when the potential builds up (no load) and the chemical potential is equalised. Batteries have a long shelf life because the reaction is only there when charge is allowed to flow and the Potential drops to permit it.
Yes, agreed. Let's see where this takes us.
What is the difference for the plates of a charged capacitor and the plates of a battery? Electrons are built up on one and depleted on the other in both cases (due to electric fields).
I thought I made it clear in post #48 where I said "A battery's voltage is because of valance electron displacement of its two metal terminals due to chemical reaction, and not electron crowding and separation due to a dielectric as in a capacitor." So no, it is not the same in both cases.
In a DC generator, the PD is caused by EM induction. Could you explain the difference in detail, as far as the charges on either side of the emf source are concerned?
The DC generator has no dielectric, therefore, its voltage will be only by EM induction as you stated, and not by charge separation and crowding or spacing out of electrons.
You ignore a component when its value is small enough to ignore it in the circumstance. In the case of the two batteries (or two capacitors) the capacity is what it is and the charge the is displaced is given by Q=CV. I assume you are familiar with that expression. The relevant capacity is small - a few pF and so is the charge imbalance (a few pC).
I agree with the above.
Without using vague terms like "floating cap" (which is something that happens when you falll in the water ), can you explain it in better terms than that?
A floating cap is a topology, not a verb. It means that one of it terminals is left "floating", i.e. it is not connected to anything.
I was suggesting that the OP could actually get an answer by considering the other capacitances involved in his experiment. Many explanations on PF involve introducing additional variables and mechanisms. I wish your objections could include some formulae or figures. It would give them some weight (PF style again).
The OP asked for a qualitative explanation, not a quantative one.
What voltage change do you refer to? Which capacitance is changing, too? If you put a DVM across two previously charged capacitors in series (or two batteries) what voltage would you expect to measure?
I was answering your previous statement where you said "with no current flowing, Inductance is hardly relevant."
I answered "And in the final state of things, with no voltage changing, neither is capacitance." So in the proper context, you should have interpretated it as I saying capacitance is not relevant if voltage is not changing. You instead interpreted it as I as saying that capacitance changed.
Ratch
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