If vector A=10i+49j, and vector B=vector A/2, then does vector

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Vector B, defined as vector A divided by 2, is calculated by halving each component of vector A. Given vector A = 10i + 49j, vector B equals 5i + 24.5j. This principle applies universally, meaning any scalar multiplication or division affects each component of the vector equally. For example, if vector C were defined as 2*A, it would result in C = 20i + 98j. Understanding these operations is crucial for vector manipulation in physics and mathematics.
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If vector A=10i+49j, and vector B=vector A/2, then does vector B=1/2(10i+49j)?
 
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k8e591 said:
If vector A=10i+49j, and vector B=vector A/2, then does vector B=1/2(10i+49j)?

Yep. So how would you write out vector B then?

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would it be 5i+24.5j?
 


Yes. The main point here is that when it is written that e.g. B = A/2, it means that each component of the vector B is half the value of the corresponding component of A. The same thing goes for multiplication by a number, e.g. C = 2*A. In that case you would have C = 20i + 98j.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks

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