If you are 8 ft away from the source, how long does the sound take to reach you?

  • Context: MHB 
  • Thread starter Thread starter riffwraith
  • Start date Start date
  • Tags Tags
    Sound Source
Click For Summary
SUMMARY

The speed of sound is established at 761.2 mph or 1116.5 feet per second (fps). To calculate the time it takes for sound to travel 8 feet, the formula used is time (t) equals distance (d) divided by velocity (v), expressed as t = d/v. Applying this formula, the time for sound to travel 8 feet is approximately 0.00716589 seconds. This calculation demonstrates the rapidity of sound propagation over short distances.

PREREQUISITES
  • Understanding of basic physics concepts, specifically sound propagation.
  • Familiarity with the formula for calculating time based on distance and velocity.
  • Knowledge of units of measurement, particularly feet and seconds.
  • Basic arithmetic skills for performing calculations.
NEXT STEPS
  • Research the speed of sound in different mediums, such as air and water.
  • Explore the effects of temperature and altitude on sound speed.
  • Learn about the Doppler effect and its relation to sound waves.
  • Investigate sound wave properties, including frequency and wavelength.
USEFUL FOR

Students studying physics, educators teaching sound concepts, and anyone interested in the mechanics of sound propagation.

riffwraith
Messages
7
Reaction score
0
The speed of sound is 761.2 mph, or, according to my math, 1116.5 fps.

If you are 8 ft away from the source, how long does the sound take to reach you?

What is the formula for doing this?

I divided 8 into 1116.5, and got 139.5 - but that doesn't seem to tell me anything. Obviously, the answer is going to be fraction of a second, but is there a real way to figure out what that # is?
 
Physics news on Phys.org
1116.5 feet : 1 sec
8 feet : ? sec

1 / 1116.5 * 8 = ~.00716 sec : faster than Superman!

80 feet: .0716 sec
800 feet: .716 sec
8000 feet: 7.16 sec
 
The relationship between distance \(d\) traveled, constant velocity \(v\) and time \(t\) may be stated:

$$d=vt\implies t=\frac{d}{v}$$

So, in this problem, we may write:

$$t\approx\frac{8\text{ ft}}{1116.4\dfrac{\text{ft}}{\text{s}}}\approx0.00716589\text{ s}$$
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 5 ·
Replies
5
Views
15K