Unveiling the Mystery of Entangled Particle Spin

In summary, the local operator can choose the angle of polarization of both photons, but they have no control over the angle of the remote photon.
  • #1
remormalise
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If you change the spin of an entangled particle without knowing its original spin, what happens to the other entangled particle?
 
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  • #2
How do you know you've changed the spin if you don't know its original value?
 
  • #3
Assume you don't need to know its original state, can you impart up spin on all particles, would this break the entanglement or down spin all the entangled particles
 
  • #4
remormalise said:
If you change the spin of an entangled particle without knowing its original spin, what happens to the other entangled particle?
An entangled pair share one wave function. So they are in a way one thing. If either one is projected into a different spin state the partner will have the same/opposite spin ( the '/' depends on the preparation).

Oh, should add that in above model, it makes no difference if you know the initial spin. If you did know it, it must have been measured (in which case the entanglement is broken ) or the preparation procedure sets an initial state.
 
Last edited:
  • #5
remormalise said:
can you impart up spin on all particles, would this break the entanglement

Yes, because this amounts to preparing a new state which is separable.
 
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  • #6
remormalise said:
If you change the spin of an entangled particle without knowing its original spin, what happens to the other entangled particle?
Nothing. You will change the total wave function of the two particles, but you can't say that something has happen to the first particle.

Consider the two-particle state
$$
| \Psi \rangle = \frac{1}{\sqrt{2}} \left[ | \uparrow \downarrow \rangle + |\downarrow \uparrow \rangle \right]
$$
Apply a rotation to the second particle such that
$$
\begin{align*}
| \uparrow \rangle &\rightarrow \frac{1}{\sqrt{2}} \left[ | \uparrow \rangle + |\downarrow \rangle \right] \\
| \downarrow \rangle &\rightarrow \frac{1}{\sqrt{2}} \left[ -| \uparrow \rangle + |\downarrow \rangle \right]
\end{align*}
$$
then the two-particle state reads
$$
| \Psi \rangle = \frac{1}{2} \left[ -| \uparrow \uparrow \rangle + | \uparrow \downarrow \rangle + |\downarrow \uparrow \rangle + |\downarrow \downarrow \rangle \right]
$$
which is still entangled.

remormalise said:
Assume you don't need to know its original state, can you impart up spin on all particles, would this break the entanglement or down spin all the entangled particles
I don't understand here. If by "all particles" you mean the two you have, then putting them both with spin-up doesn't corresponds to an entangled state.
 
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  • #7
Gentlemen, I am very grateful for your input to help me understand how entanglement works. I am not a physicist, but I have a deep and long-standing interest in how our universe works.

My apologies if my question was not precise or constrained enough, however, your answers have provided me with an increased understanding, which is all I am ever after.

Many thanks.
 
  • #8
Dear Sir/ Madam,

I've recently seen the excellent youtube video on "Quantum Entanglement & Spooky Action at a Distance" by Veritasium - but either I'm not understanding something - or there seems to be something missing from the explanation.

It seems that the operator can choose the ANGLE of polarisation of both entangled photons (+_180 degrees) - even if one photon is very far away - is this correct ??
 
  • #9
Abiologist1 said:
I've recently seen the excellent youtube video on "Quantum Entanglement & Spooky Action at a Distance" by Veritasium - but either I'm not understanding something - or there seems to be something missing from the explanation.
You cannot learn quantum mechanics from videos on the internet. They're fun, they're interesting, some are better than others, but there is always something missing.
It seems that the operator can choose the ANGLE of polarisation of both entangled photons (+_180 degrees) - even if one photon is very far away - is this correct ??
The local operator can choose to measure the polarization on any axis they want; whatever result they get, a measurement of the other photon will produce the opposite result. Say the operator holds their polarizer at an angle of ##\theta## degrees. If their photon passes through the filter, they have just measured the photon to be polarized at that angle; if it doesn't pass they've just measured it to be polarized at 90 degrees to that angle. Either way, if we measure the other photon with a polarizer at the same angle, we will find the opposite polarization result.

However, that doesn't mean that the operator has any control over the angle of the remote photon. No matter what anyone does and no matter which angles are chosen for the two measurements, the remote observer will always find that half the photons clear his filter and half are absorbed. The remote observer has no way of knowing that the photons are entangled or even whether the operator came into work that day until both sides get together after the fact and compare notes. Only then do they see that although their individual results are completely random, they always get opposite results when the polarizers are at the same angle.
 
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  • #10
Nugatory said:
However, that doesn't mean that the operator has any control over the angle of the remote photon. No matter what anyone does and no matter which angles are chosen for the two measurements, the remote observer will always find that half the photons clear his filter and half are absorbed.

regardless of the percentage which clear the filter of the local operator ? - or do you mean only in the case that half the photons clear the local operator filter and half are absorbed ? Thankyou for your detailed first reply (!)
 
  • #11
Abiologist1 said:
regardless of the percentage which clear the filter of the local operator ? - or do you mean only in the case that half the photons clear the local operator filter and half are absorbed ?
The percentage that clears the local operator’s filter is always 50%, no matter what the angle of the filter, just as with the remote filter.

(And I should add that there are serious practical difficulties in actually performing this experiment in exactly this form - this is a thought experiment as described)
 
  • #12
Nugatory said:
(And I should add that there are serious practical difficulties in actually performing this experiment in exactly this form - this is a thought experiment as described)

OK - so what would be a better experiment ? I am aware that someone thinks that a hidden variable determining whether any photon is detected at all, or whether no photon is detected by both local and remote operators, could give results that allow the probabilities actually detected but still be consistent with non-quantum phenomena (see Explained & Debunked_ Quantum Entanglement & Bell Test Experiments - YouTube). Do you think this is a possibility ? Many thanks in advance.
 

1. What is entangled particle spin?

Entangled particle spin is a phenomenon in quantum mechanics where two or more particles are connected in such a way that the state of one particle is dependent on the state of the other, regardless of the distance between them. This means that if the spin of one particle is measured, the spin of the other particle will be the opposite, even if they are separated by great distances.

2. How does entangled particle spin work?

The exact mechanism of entangled particle spin is still not fully understood, but it is believed to involve a combination of quantum superposition and quantum entanglement. Essentially, the particles are in a state of superposition, meaning they exist in multiple states simultaneously, until one of the particles is measured, at which point the other particle's state is determined.

3. What is the significance of entangled particle spin?

Entangled particle spin has significant implications for quantum computing and communication. It allows for the creation of qubits, which are the basic units of quantum information, and can potentially lead to faster and more secure methods of computing and communication.

4. Can entangled particle spin be observed in everyday life?

No, entangled particle spin is a phenomenon that occurs on a very small scale and is only observable in controlled laboratory settings. It is not something that can be observed in everyday life.

5. What are the challenges in studying entangled particle spin?

One of the main challenges in studying entangled particle spin is the difficulty in creating and maintaining entanglement between particles. This requires precise and delicate equipment, as well as a controlled environment to prevent any external factors from disrupting the entanglement. Additionally, the interpretation of the results of experiments involving entangled particle spin can be complex and require a deep understanding of quantum mechanics.

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