I'm looking for a local minimum point that doesn't show up when....

Click For Summary

Homework Help Overview

The discussion revolves around finding a local minimum of a function, specifically analyzing the behavior of its derivative. The function in question appears to be related to arctan and logarithmic expressions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of having one real root of the derivative, questioning how this relates to the existence of local extrema. There are inquiries about the function's behavior and the methods used to identify critical points.

Discussion Status

The conversation includes various interpretations of the function's critical points and the nature of the roots of its derivative. Some participants suggest that the original poster may have made an error in their analysis, while others express confusion about the existence of both a maximum and a minimum given the derivative's characteristics.

Contextual Notes

There is mention of complex roots and their relevance to real extrema, as well as the need for clarity in mathematical expressions. The discussion reflects uncertainty regarding the function's definition and the implications of its increasing nature.

Wi_N
Messages
119
Reaction score
8
Member warned that the template must be filled in with a problem statement and the work shown

Homework Statement


I set the derivative to 0. i get 1 real root a max point and 2 imaginary. How can i find that local min?

what techniques are available?
 
Physics news on Phys.org
Wi_N said:

Homework Statement


I set the derivative to 0. i get 1 real root a max point and 2 imaginary. How can i find that local min?

what techniques are available?
How do you know that the critical point is maximum? What is the function you want to find the local minimum of?
 
ehild said:
How do you know that the critical point is maximum? What is the function you want to find the local minimum of?

i plotted the graph. there is a min point and a max point. but only the max point is attainable through der=0

arctanx -ln(x)/6 - x/3

max point at x=1 but the min x=0.28 can't be found using der.
 
Wi_N said:
i plotted the graph. there is a min point and a max point. but only the max point is attainable through der=0

arctanx -ln(x)/6 - x/3

max point at x=1 but the min x=0.28 can't be found using der.
How did you get the other roots? Show your work.
 
ehild said:
How did you get the other roots? Show your work.

thank you for your help. i must be going crazy or blind but i solved it.
 
Please use parentheses in your equations to make them clear. They do not cost anything. ;>)

Note: Since arctan is a strictly increasing function, you might get a simpler problem by ignoring the arctan. It depends on whether the problem is ##atan( -ln(x)/6 - x/3 )## or ##atan( -ln(x)/6 ) - x/3 ##.

CORRECTION: I see that the function is atan(x)-ln(x)/6-x/3. Maybe that should have been obvious to me.
 
Last edited:
Wi_N said:
thank you for your help. i must be going crazy or blind but i solved it.
It would be useful for other people if you showed the way of solution
 
  • Like
Likes   Reactions: SammyS
If there is only one real zero of the derivative (as stated in post #1), there can not be a local max and a local min (as stated in post #3). Complex derivative zeros will not add a local extreme point on the real line.
 
FactChecker said:
If there is only one real zero of the derivative (as stated in post #1), there can not be a local max and a local min (as stated in post #3). Complex derivative zeros will not add a local extreme point on the real line.
There are three real zeros of the derivative, but one is at negative x where the function is not defined. The OP made some mistake, and he found it an got the minimum, see Post #5
 
  • Like
Likes   Reactions: FactChecker
  • #10
ehild said:
There are three real zeros of the derivative, but one is at negative x where the function is not defined. The OP made some mistake, and he found it an got the minimum, see Post #5
Right. I just wanted to point out that there was a mistake that was clear just from basic principles.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
30
Views
3K
  • · Replies 46 ·
2
Replies
46
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K