How Do You Solve for v in Physics Equations?

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The discussion revolves around solving for the variable v in a physics equation related to optics. The initial attempt at a solution yielded a value of -1.06 cm, indicating the position relative to a wall. Participants noted the absence of a clear problem statement, which hindered the ability to provide assistance. Eventually, the original poster acknowledged a mistake in their calculations. The conversation highlights the importance of clearly presenting problems in physics for effective collaboration.
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Homework Statement



the ans is B for this question

Homework Equations





The Attempt at a Solution


my working is 1.59/2.0 + 1/v = (modulus of 1-1-59) /( -4 )
my v is -1.06cm. which is 1.06cm to the right from the tleft wall of plastic ball
 
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desmond iking said:

Homework Statement



the ans is B for this question

Homework Equations





The Attempt at a Solution


my working is 1.59/2.0 + 1/v = (modulus of 1-1-59) /( -4 )
my v is -1.06cm. which is 1.06cm to the right from the tleft wall of plastic ball

What question? Did you forget to attach something
 
desmond iking said:

Homework Statement



the ans is B for this question

Homework Equations





The Attempt at a Solution


my working is 1.59/2.0 + 1/v = (modulus of 1-1-59) /( -4 )
my v is -1.06cm. which is 1.06cm to the right from the tleft wall of plastic ball

It's going to awfully hard for anyone to give you any help based on the total lack of a problem statement.
 
phinds said:
It's going to awfully hard for anyone to give you any help based on the total lack of a problem statement.

her's the question
 

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you could draw a ray diagram to locate the image.
 
Sorry, I have found my mistake finally
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
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