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saldana787
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Homework Statement
Here is the full question.
Consider a curve defined by 2y^3 + 6x^2y - 12x^2 + 6y = 1 and dy/dx = (4x-2xy)/(x^2+y^2+1).
The line through the origin with slope -1 is tangent to the curve at point P. Find the x - coordinate and y - coordinate of point P.
Homework Equations
2y^3 + 6x^2y - 12x^2 + 6y = 1
dy/dx = (4x-2xy)/(x^2+y^2+1)
The Attempt at a Solution
The equation for the line through (o,o) with slope -1 which I found to be y = -x. I tried to plug -x back into original equation but came up with a weird expression for y.
Thanks for any help in advance.
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