1. The problem statement, all variables and given/known data Here is the full question. Consider a curve defined by 2y^3 + 6x^2y - 12x^2 + 6y = 1 and dy/dx = (4x-2xy)/(x^2+y^2+1). The line through the origin with slope -1 is tangent to the curve at point P. Find the x - coordinate and y - coordinate of point P. 2. Relevant equations 2y^3 + 6x^2y - 12x^2 + 6y = 1 dy/dx = (4x-2xy)/(x^2+y^2+1) 3. The attempt at a solution The equation for the line through (o,o) with slope -1 which I found to be y = -x. I tried to plug -x back into original equation but came up with a weird expression for y. Thanks for any help in advance.