Impossible Sp. Relativity question?

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Homework Help Overview

The discussion revolves around a problem in special relativity involving the emission of a photon by a particle and the implications for energy and momentum conservation. Participants are exploring the concept of rest mass and its invariance in the context of particle interactions and energy transformations.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to reconcile the conservation of energy and momentum with the behavior of the particle before and after photon emission. Questions arise regarding the nature of rest mass and whether it changes during the process.

Discussion Status

The discussion is active, with various interpretations being explored regarding the rest mass of the particle and the conditions under which it emits a photon. Some participants are providing insights into the necessity of the particle being in an excited state to emit energy, while others are questioning the assumptions made about energy sources and mass changes.

Contextual Notes

There is an ongoing debate about the implications of mass-energy equivalence and the invariance of rest mass, with references to specific equations and principles of special relativity. Participants are navigating the complexities of these concepts without reaching a definitive conclusion.

Zorba
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Homework Statement


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Homework Equations



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The Attempt at a Solution



I think this question is impossible, i keep getting an answer that says that the particle recoils with a velocity > c_0.

Cons. Of Energy
E_1 = E_2 + E_\gamma
m_0c^2 = \gamma m_1 c^2 + E_\gamma

Cons. Of Mom.
0 = P_1 - P_\gamma
\gamma m_1 = \frac{E_\gamma}{vc}

\Rightarrow m_0 c^2 = E_\gamma \cdot \frac{c}{v} + E_\gamma

Some manipulation yields:
v = \frac{cE_\gamma}{m_0c^2 - E_\gamma}

And I plug the numbers in and I get 1.46c. ... !
 
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The correct equation for the total energy is

E = γm0c2, where m0 is the rest mass.
 
But does the rest mass not change, ie. the restmass before the photon is emitted, is different from after the rest mass is emitted? How else would the photon come about then..?
 
The rest mass is always the same. In this case the given 6x10-30 kg is the rest mass m0. It is a number less than the initial mass because the particle is in an excited state before it emits the photon. You need to find the kinetic energy, which is the difference between the total energy and the rest mass energy. Note that you can write the total energy as

E=\sqrt{p^2c^2+m_0^2c^4}

Use the momentum conservation equation to eliminate p, subtract the rest mass energy and you are done.
 
kuruman said:
The rest mass is always the same.

Even if I have a particle that pumps out 100 photons, its rest mass is still invariant? That makes no sense to me, where is the energy coming from?

The particle initially is at rest, so it can't come from kinetic energy, thus it must come from rest mass energy, thus its rest mass energy must decrease after emitting the photon, thus its mass must decrease? Is this line of reasoning all wrong?
 
Zorba said:
Even if I have a particle that pumps out 100 photons, its rest mass is still invariant? That makes no sense to me, where is the energy coming from?

The particle initially is at rest, so it can't come from kinetic energy, thus it must come from rest mass energy, thus its rest mass energy must decrease after emitting the photon, thus its mass must decrease? Is this line of reasoning all wrong?
The particle is at rest, but in an excited state. If it were in the ground (lowest energy) state, it would not be able to emit a photon. It got in that excited state perhaps because it absorbed a photon or it underwent a collision with another particle and picked some energy, or whatever. That's where the energy is coming from.
 
kuruman said:
The particle is at rest, but in an excited state. If it were in the ground (lowest energy) state, it would not be able to emit a photon. It got in that excited state perhaps because it absorbed a photon or it underwent a collision with another particle and picked some energy, or whatever. That's where the energy is coming from.

But, but, but...:biggrin: where in the question does it say that? I have to assume that?!
 
You don't have to assume anything. You know that a particle that is in the ground state and at rest cannot possibly emit a photon. That's because, by definition, the lowest possible energy state is the ground state and furthermore does not any have kinetic energy in that frame of reference that it can trade for photon energy. Like you say, if the particle emitted a photon, where would the photon energy come from? Therefore the particle that is given in the problem must be in an excited state. Either that or Energy Conservation does not hold. Take your pick.
 
Hmm interesting, it seems to imply that a particle cannot "degrade" so to speak without some energy input, although I thought mass-energy equivalence would allow this - just have some of that mass converted into energy to emit the photon, but that seems to break postulate wrt to invariance of c...I think.

Would I be correct in saying that rest mass is an entirely invariant quantity?

(thanks a lot for answering all these qustions)
 

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