Impossible vector problem. Help

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The discussion revolves around solving for an unknown vector when the overall resultant force and several known vectors are given. The approach involves using vector subtraction, where the unknown vector can be calculated by reversing the direction of known vectors and the resultant force. Participants emphasize the importance of breaking down vectors into their components to simplify calculations. The challenge arises when only the overall magnitude is known, as both magnitude and angle are necessary for a complete solution. Ultimately, including the overall angle allowed for a resolution to the problem.
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Most of the time, one uses vectors to find an overall magnitude acting on something, but I need to go in reverse.

Say I know there are a slew of charges and the center one feels a force of some magnitude and there is one undefined vector (magnitude and angle unknown) I would think if you know the overall vector, one could calculate the missing vector in terms of magnitude and angle.

I want to solve for this unknown vector but I have no idea how. It seems impossible.
 
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Essentially, you are saying that you have the equation
x_1+ x_2+ ...+ x_n= F where x_1,... x_{n-1} are the known vector forces, x_n is the one unknown vector and F is the known resultant. Solve that exactly the way you would any equation: x_n= F- x_1- x_2- ...- x_{n-1}. Essentially that "subtraction" on the right is just like addition of vectors except that you reverse the direction of x_1,... x_{n-1}. You might find the calculation easier as -x_n= x_1+ x_2+ ...+ x_{n-1}- F. That is, you just reverse the direction of F, add the vectors and then reverse the direction of the result to find x_n.
 
Consider the vector equation:
\vec{F}_{net} = \vec{F}_{known} + \vec{F}_{unknown}

Where F(net) is the net force at the center and F(known) is the sum of the known forces from each charge. To solve for the unknown vector, F(unknown), just subtract.

(Looks like Halls beat me to it.)
 
Overall Magnitude = sqrt( (mag1*cos(A) + mag2*cos(B) + mag3*cos(C))^2 + (mag1*sin(A) + mag2*sin(B) + mag3*sin(C))^2)

I don't think it's that easy since the angle and magnitude go hand in hand. I need to solve for both mag1 and angle A. I'm sorry if I forgot to really point that out.

I thought it would be something more involved along the lines of langrange multipliers.
 
relativitydude said:
I don't think it's that easy since the angle and magnitude go hand in hand. I need to solve for both mag1 and angle A. I'm sorry if I forgot to really point that out.
Instead of using overall magnitude, find the vector components. If you write the vectors in terms of their components, adding and subtracting will be a breeze. Once you find the components of the unknown vector, then you can determine its magnitude and angle.

I thought it would be something more involved along the lines of langrange multipliers.
:eek:
 
Yes, using the horizontal and vertical components would be really easy but I only know the overall magnitude :(
 
If all you know is the magnitude, then you can't solve the problem. I suspect that you know both the magnitude and the angle. Use those to find the components.
 
relativitydude said:
Most of the time, one uses vectors to find an overall magnitude acting on something, but I need to go in reverse.

Say I know there are a slew of charges and the center one feels a force of some magnitude and there is one undefined vector (magnitude and angle unknown) I would think if you know the overall vector, one could calculate the missing vector in terms of magnitude and angle.

I want to solve for this unknown vector but I have no idea how. It seems impossible.

Working with vectors is essential in both mathematics and physics. Here is an intro and some exercises to test your knowledge...courtesy of PF :wink:

Here You Go

regards
marlon
 
Thanks for all the help. I guess not having an overall angle made the problem, well, impossible. Including it brought me quickly to the answer.
 
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