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## Homework Statement

Solve the integral [tex]\int[/tex][tex]\frac{1}{\sqrt[3]{x-1}}[/tex]. Upper limit of integration is 1 while lower limit is 0.

## Homework Equations

N/A.

## The Attempt at a Solution

The only thing that I'm sure about is that the antiderivative of the integral is [tex]\frac{3}{2}[/tex](x-1)^(2/3) + C. I know that i need to take the limit of the integral, but I am not sure what the limit should be approaching. 1 Maybe? Since f(x) DNE there. Since I'm stuck on that, I'm kinda stuck on everything else besides the antiderivative.

Any help would be great! Thanks.