- #1
kingwinner
- 1,270
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Homework Statement
Evaluate
∞
∫ [1/sqrt(2 pi)] x e-x2/2 dx
-∞
∞
∫ [1/sqrt(2 pi)] x2 e-x2/2 dx
-∞
2. Relevant concepts
Improper integrals
The Attempt at a Solution
In my notes, it says the the first integral is 0 since
∞
∫ odd function =0
-∞
But I am having a lot of trouble understanding this.
Code:
∞
∫ f(x)dx
-∞
by definition is equal to
0 b
lim ∫ f(x)dx + lim ∫ f(x)dx
a->-∞ a b->∞ 0
∞
∫ odd function =0 ? Is this even correct?
-∞
What is the correct way to evalaute the integral?
Also, how can I compute the second integral?
Thanks for any help!