Improving Numerical Approximations of Limits: A Sample Exam Question

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Homework Help Overview

The discussion revolves around a sample exam question related to numerical approximations of limits, specifically focusing on the expression L = lim_{h → 0} f(h) and its relation to the error terms c_6 h^6, c_9 h^9, etc. Participants are exploring how to combine values of f(h) and f(h/2) to improve the estimate of L.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to express f(h) in terms of L and the error terms, and are questioning how to derive f(h/2) from this. They are discussing the formulation of a linear combination of f(h) and f(h/2) that yields a better approximation of L. There is also uncertainty regarding the specific methods studied in class that apply to this problem.

Discussion Status

The discussion is active, with participants sharing their interpretations and attempting to clarify their understanding of the problem. Some guidance has been offered regarding the formulation of the linear combination, but there is still confusion about the relevant methods and concepts.

Contextual Notes

Participants express uncertainty about the section of the textbook that relates to the problem and the specific methods they have studied that could apply to this scenario.

JamesF
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I'm having trouble with a sample exam question. I don't really understand the question, don't know what section of the book it relates to, and don't have any idea on how to solve it. I might be in trouble :)

Can anyone provide any suggestions or guidance on how I might go about solving this problem? Again, I'm not even really sure what's being asked.


Homework Statement


Suppose that L = \lim_{h \rightarrow 0} f(h)
and L -f(h) = c_6 h^6 + c_9 h^9 + \cdots

Find a combination of f(h) and f(h/2) that is a much better estimate of L
 
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Well, if L -f(h) = c_6 h^6 + c_9 h^9 + \ldots , then surely you can say that f(h) =L-( c_6 h^6 + c_9 h^9 + \ldots) right?...What does that make f(h/2)?...Basically you want to use this to find some linear combination of f(h) and f(h/2) that is closer to L than f(h) is.
 
gabbagabbahey said:
Well, if L -f(h) = c_6 h^6 + c_9 h^9 + \ldots , then surely you can say that f(h) =L-( c_6 h^6 + c_9 h^9 + \ldots) right?...What does that make f(h/2)?...Basically you want to use this to find some linear combination of f(h) and f(h/2) that is closer to L than f(h) is.

thanks for your reply. Let's see if I understand

if f(h) = L - c_6 h^6 - c_9 h^9 - \cdots
and f(\frac{h}{2}) = L - \frac{c_6 h^6}{64} - \frac{c_9 h^9}{512}

what I'm trying to find is a_0, a_1 such that a_0 f(h) + a_1 f(\frac{h}{2}) \approx L. Is that right?

I'm still somewhat confused as to what this problem relates to, ie what methods have we studied would this problem apply to
 
JamesF said:
thanks for your reply. Let's see if I understand

if f(h) = L - c_6 h^6 - c_9 h^9 - \cdots
and f(\frac{h}{2}) = L - \frac{c_6 h^6}{64} - \frac{c_9 h^9}{512}

what I'm trying to find is a_0, a_1 such that a_0 f(h) + a_1 f(\frac{h}{2}) \approx L. Is that right?

You're not even looking for something this restrictive, you just want a_0 f(h) + a_1 f(\frac{h}{2})
to be closer to L than f(h) was...so as long as a_0 f(h) + a_1 f(\frac{h}{2})-L< c_6 h^6 +c_9 h^9 + \cdots, then it is mission accomplished. ...what happens if you take a_0=1 and a_1=-2^6?

I'm still somewhat confused as to what this problem relates to, i.e. what methods have we studied would this problem apply to

I'm not sure what methods you've studied :-p, but I think this is basically the beginning of an algorithm to numerically approximate the limit L.
 

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