In-frame time derivative proof

yakattack
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Could someone please help with this question.

For non-inertial frames show that the in-frame time derivative D obeys:
D(fa)=fDa+df/dta

Where f is a scalar function and a is a vector.

I know that Df=df/dt and that Da= the sum of the derivatives of the components of a times the relavant basis vector. But can't seem to apply this to prove the question.
 
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Well for the non inertial observer, the a vector is a time dependent function. So actually you get \vec{a} = a \cdot \vec{e_t}. Hence the D \vec{a} = a \cdot \frac{d \vec{e_t}}{dt}.

marlon
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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