- #1

pondzo

- 169

- 0

1+1=√1 +1

=√(-1)(-1) +1

= (√(-1))(√(-1)) +1

= (i)(i) +1

= i

^{2}+1

= -1 + 1

= 0

I know I'm not the first to come up with this 'proof', and i have been told that the problem lies with splitting the radical between the 2nd and 3rd lines of working. But in the complex number system there is no problem with going from, say, √(-4) = √(-1)(4) = 2i so why is there a problem with the above working, isn't it the same line of thought?

thanks, Michael.