Inclined Glass Wedge Diffraction - Help

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SUMMARY

The discussion focuses on calculating the wavelength of incident light on an inclined glass wedge, where the upper edge is inclined at an angle of γ = 0.05°. The distance between adjacent dark streaks in the reflected light is given as △X = 0.21 mm, and the refractive index of the glass is n = 1.5. The relevant equation for this problem is d sin α = n λ, which relates the thickness of the film, the angle of incidence, and the wavelength of light. This scenario is identified as a thin-film interference problem.

PREREQUISITES
  • Understanding of thin-film interference principles
  • Familiarity with the equation d sin α = n λ
  • Knowledge of refractive indices and their implications
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the principles of thin-film interference in detail
  • Learn how to derive the wavelength from interference patterns
  • Explore the impact of varying angles on interference fringes
  • Investigate the use of refractive index in optical calculations
USEFUL FOR

Students in physics or optics courses, educators teaching interference phenomena, and anyone interested in practical applications of thin-film optics.

Zaknife
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Homework Statement


Monochromatic beam of incident light on the surface of the glass wedge,
whose upper edge is inclined at an angle of γ = 0.05 ° from the base. In reflected light
observe a number of interference fringes, the distance between adjacent
dark streaks is △X = 0.21 mm. Calculate the wavelength λ of the incident light.
Refractive index of glass n = 1.5.


Homework Equations


d \sin \alpha = n \lambda


The Attempt at a Solution


I need a guidance ! Is it a thin-film problem ?
 
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Need a picture of this setup.
 

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