Inclined Plane with Pulley: Finding Velocity with Tension and Acceleration

AI Thread Summary
A 10 kg mass on a frictionless inclined plane at 30 degrees is connected to a pulley with a tension of 75 N. The correct approach involves using the equation T - mgsinθ = ma to find acceleration, where mgsinθ is calculated as 50 N. After determining the acceleration to be 2.5 m/s², the final velocity after 2 seconds is calculated using Vf = Vi + at, resulting in a velocity of 5 m/s. The initial misunderstanding stemmed from incorrectly calculating the forces acting on the mass. The final answer aligns with the book's solution, confirming the correct methodology.
brake4country
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Homework Statement


A 10 kg mass is on a frictionless inclined plane 30 degrees to the horizontal. At the top of the plane is a pulley that has a rope attached to mass with tension T = 75 N. If the mass starts from rest, what is its velocity after 2 seconds?

Homework Equations


F = ma
Vf=Vi + at

The Attempt at a Solution


So my book lists the formula as T = mgsinθ + ma. I set the problem up pretty much the same as:
∑Fx = max
75 N - 10 N = (10 kg) a
My acceleration is 6.5 m/s2. Plugging this value into vf=vi + at, I get 13.0 m/s but my book says it's supposed to be 5 m/s. What am I doing wrong? Thanks in advance!
 
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brake4country said:

Homework Statement


A 10 kg mass is on a frictionless inclined plane 30 degrees to the horizontal. At the top of the plane is a pulley that has a rope attached to mass with tension T = 75 N. If the mass starts from rest, what is its velocity after 2 seconds?

Homework Equations


F = ma
Vf=Vi + at

The Attempt at a Solution


So my book lists the formula as T = mgsinθ + ma. I set the problem up pretty much the same as:
∑Fx = max
75 N - 10 N = (10 kg) a
Where did you get that 10 N from?
 
The x component of the weight: -mgsinθ
 
brake4country said:
The x component of the weight: -mgsinθ
m=10 kg, g=10 m/s2, θ=30° . How would it give 10 N ?
 
I see. Well, I redid this problem and I did a force table. My T is 75 N, my x component of the force is -50 N. If I set up the problem I get:
T - mgsinθ = ma
75-50 = 10 a
a = 2.5 m/s^2

The answer is 5 m/s^2.
 
I totally misread this problem and it serves me right for not paying close attention. This is a two part problem. I solved for the acceleration using F=ma, which is 2.5 m/s^2. Then with the known time (2 s), I plugged it into the equation Vf=Vi + at. Vf = 5 m/s.
 
Well done at the end!
 
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