as in the diagram below, mass m1 is placed above mass m2 on a sloped incline with an angle of b degrees. the frictional coefficient between the two masses is C1 and the coeficient between mass 2 and the slope is C2. find the acceleration of the masses. http://picasaweb.google.com/devanlevin/DropBox?authkey=sbH95pBl_D8#5273088118963403586 [Broken] after dividing the vectors into components i said N1=(m1)gcosb f1=(C1)(m1)gcosb N2=N1+(M2)gcosb=(M1+M2)gcosb f2=(C2)(M1+M2)gcosb for mass 1 F=m1gsinb-f1=m1a =(m1)gsinb-(C1)(m1)gcosb=m1a a1=g(sinb-C1cosb)=gcosb(tgb-C1) meanin that when C1 is equal to tanb, body 1 will not move relative to body 2 or will not move relative to the slope? now for body2 F=m2gsinb+f1-f2=m2a------> is this correct?? after opening i get a2=m2gcosb(tgb-C2)+m1gcosb(C1-C2) is this correct?