Homework Statement

$$\lim_{x \to {4}}\frac{4 - x^2}{2 - \sqrt{x}}$$

The Attempt at a Solution

$$\lim_{x \to {4}}\frac{4 - x^2}{2 - \sqrt{x}} \cdot \frac{2 + \sqrt{x}}{2 + \sqrt{x}}$$

$$= \frac{x(4-x)(2-\sqrt{x})}{(4-x)} = x(2-\sqrt{x})$$

this equals zero, but is the limit indeterminate at this point?

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rock.freak667
Homework Helper
I think you expanded the numerator incorrectly

thanks! it was a missed minus sign.

4-x^2 = (2-x)*(2+x)