Inductance of a Trace: Qualitative Analysis

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In a tapered PCB trace, the inductance is greater on the narrower side due to increased current density, as the same current flows through a smaller cross-sectional area. This higher current density leads to a stronger magnetic field, which contributes to increased inductance. While capacitance is higher on the wider side due to its larger area, the inductance behavior is influenced by the geometry and current distribution. The comparison to two parallel traces illustrates that a wider trace effectively reduces inductance, as the inductance of parallel paths is lower. Understanding these relationships helps clarify why inductance varies with trace width.
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If I have a trace on a PCB that is wider on the left side and then tapers down to a narrower trace on the right side, why is it that the inductance is greater on the narrower side? I realize there are equations that describe this behavior but I'm just trying to get a qualitative understanding of this.

I can see how the capacitance on the wider side would be greater than the capacitance on the narrower side (due to area) but I can't quite see why the inductance is greater on the narrower side. I know that the current density J = I / A and given that we are pushing the same amount of current through the trace, the current density would be greater in the trace with less area. Will a higher current density result in a higher indutance -- is this because it is able to store more energy?
 
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If the trace is twice as wide, it is like having two single-width traces in parallel. The inductance of the parallel combination is 1/2 that of the single width trace.
 
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