Inelastic and elastic collision problems

In summary, a rubber bullet weighing 8 g was fired into a 2.5 kg pendulum bob, initially at rest. In case 1, the bullet becomes embedded in the bob and causes it to rise 6.0 cm vertically. Using the conservation of energy equation, we can calculate the initial speed of the bullet and the amount of kinetic energy lost in the collision. In case 2, the bullet bounces off in the opposite direction and the bob rises 6.0 cm. By using the conservation of momentum equation, we can find the change in velocity of the bullet. To solve for the initial and final velocities, we also need to use the conservation of kinetic energy equation.
  • #1
mdwjun
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1. An 8 g rubber bullet was fired into a 2.5 kg pendulum bob, initially at rest, and becomes embedded in it. The pendulum rises a vertical distance of 6.0 cm.Calculate the initial speed and how much kinetic energy is lost in this collision?

2. An 8 g rubber bullet was fired into a 2.5 kg pendulum bob, initially at rest, and bounces off into the opposite direction. It rises 6.0 cm vertically. (elastic case) What is the velocity of the bob after the collision? Use conservation momentum to find the change in velocity of the bullet. Use conservation of Kinetic energy to find initial velocity of bullet and final velocity of the bullet.

I heard that I needed to use the inelastic collision and the conservation of energy equation for number 1.
0.5*mass*initial velocity^2 +mass*gravitational pull* initial height=0.5*mass*final velocity^2 +mass*gravitational pull* final height.

I triedto solve but could not because i did not know the initial velocity of the bullet and the final velocity.
 
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  • #2
-sigh- help
 
  • #3


I would like to clarify that both problems involve conservation of momentum and energy, but they are different types of collisions - inelastic and elastic. In an inelastic collision, the objects stick together after the collision and move with a common velocity, while in an elastic collision, the objects bounce off each other with no loss of kinetic energy.

For the first problem, we can use the conservation of momentum equation to find the initial velocity of the bullet. Since the pendulum bob was initially at rest, its initial momentum is zero. Therefore, the initial momentum of the system is equal to the momentum of the bullet before the collision. We can write this as:

m_bullet * v_bullet = (m_bullet + m_bob) * v_final

where m_bullet is the mass of the bullet, v_bullet is its initial velocity, m_bob is the mass of the pendulum bob and v_final is the common velocity after the collision. We also know that the energy is conserved in this case, so we can use the conservation of energy equation to find the initial velocity of the bullet:

0.5 * m_bullet * v_bullet^2 = 0.5 * (m_bullet + m_bob) * v_final^2

We also know that the pendulum rises a vertical distance of 6.0 cm, so we can use the conservation of energy equation again to find the initial velocity of the bullet:

m_bullet * g * h = 0.5 * (m_bullet + m_bob) * v_final^2

where g is the gravitational acceleration and h is the height the pendulum rises. Now we have three equations and three unknowns (v_bullet, v_final, and h), so we can solve for all of them. Once we find the initial velocity of the bullet, we can use the conservation of energy equation to find the kinetic energy lost in the collision:

KE_lost = 0.5 * m_bullet * v_bullet^2 - 0.5 * (m_bullet + m_bob) * v_final^2

For the second problem, we have an elastic collision, so we can use the conservation of momentum equation to find the final velocity of the bullet. We can write this as:

m_bullet * v_bullet = (m_bullet + m_bob) * v_final

We also know that the bob rises a vertical distance of 6.0 cm, so we can use
 

1. What is the difference between an inelastic and an elastic collision?

An inelastic collision is one in which the total kinetic energy of the system is not conserved, meaning that some of the kinetic energy is lost in the form of heat or deformation. In contrast, an elastic collision is one in which the total kinetic energy is conserved, meaning that no energy is lost during the collision.

2. How do you calculate the final velocities of objects in an inelastic collision?

In an inelastic collision, the final velocities of the objects can be calculated using the conservation of momentum principle, which states that the total momentum before the collision is equal to the total momentum after the collision. This can be expressed as m1v1i + m2v2i = m1v1f + m2v2f, where m is the mass of the object and v is its velocity. Solving for v1f and v2f will give you the final velocities.

3. What is the coefficient of restitution and how is it related to elastic collisions?

The coefficient of restitution is a measure of how much of the kinetic energy is conserved in an elastic collision. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach. In other words, it is the ratio of the final velocity to the initial velocity. A higher coefficient of restitution indicates a more elastic collision, where more kinetic energy is conserved.

4. Can an inelastic collision be perfectly inelastic?

Yes, an inelastic collision can be perfectly inelastic, meaning that the objects stick together after the collision and move with a common final velocity. This occurs when the coefficient of restitution is equal to 0. In this case, all of the kinetic energy is lost and is converted into other forms of energy, such as heat or sound.

5. How does the mass and velocity of objects affect the outcome of an inelastic collision?

The mass and velocity of objects play a crucial role in determining the outcome of an inelastic collision. In general, the greater the mass and velocity of an object, the greater its momentum and kinetic energy, and the greater the effect it will have on the final velocities of the objects involved in the collision. However, the relative masses and velocities of the objects also play a role in determining the final velocities, as seen in the conservation of momentum equation.

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