Inelastic Collision of 2 Carts - Displacement

AI Thread Summary
A 15.0 kg toy cart collides head-on with a 10.0 kg cart, resulting in an inelastic collision where they stick together. The initial velocities are 5.5 m/s to the right for the first cart and 4.0 m/s to the left for the second cart. After the collision, the combined velocity is calculated to be 1.7 m/s. The frictional force, determined by the coefficient of friction of 0.40, results in a deceleration of 3.92 m/s². The carts slide a distance of 0.37 meters from the collision point before coming to a stop.
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Homework Statement


A 15.0 kg toy cart is traveling at 5.5 m/s to the right when it collides head on with a 10.0 kg cart traveling at 4.0 m/s to the left. The objects collide and stick togethere. The coefficient of friction between the wheels of the cart and the floor is 0.40. How far will the carts slide from the location of the collision?

ma = 15 kg
va = 5.5 m/s
mb = 10 kg
vb = 4.0 m/s
μ = 0.4

Homework Equations


Assuming right is positive.

mava + mbvb = ma+b * va+b
Fnet = ma
v2^2 = v1^2 + 2ad

The Attempt at a Solution


mava + mbvb = ma+b * va+b
15(5.5) + 10(-4) = 25 * va+b
42.5 = 25 * va+b
va+b = 1.7 m/s

Fnet = ma
Ff = ma
Fnμ = ma
- Since there is no vertical acceleration Fn = Fg
9.8(0.4) = a
a = -3.92 m/s

this is where I get stuck

Edit: I tried doing this but I'm not sure if I'm right.

v2^2 = v1^2 + 2ad
0 = (1.7)^2 + 2(-3.92)d
-2.89 = -7.84d
d = 0.37 m
 
Last edited:
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Yup. That works :smile:
 
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