Inertia of Momentum: Initial CG Y Coordinate

  • Thread starter Thread starter Krobinson2851
  • Start date Start date
  • Tags Tags
    Inertia Momentum
AI Thread Summary
To find the initial y-coordinate of the center of gravity for the dance floor and the three couples, apply the center of mass formula for y-coordinates. The total mass includes the mass of the dance floor (1100 kg) and the three couples (300 kg total). The calculation involves determining the weighted average of the y-coordinates of all masses involved. If difficulties arise, sharing your calculations can help others provide more targeted assistance. The key is to systematically apply the center of mass equations to solve the problem.
Krobinson2851
Messages
1
Reaction score
0

Homework Statement



Given: A flat dance floor of dimensions lx = 17mbyly =15mandhasamassofM = 1100 kg. Use the bottom left corner of the dance floor as the origin. Three dance couples, each of mass m = 100 kg start in the top left, top right, and bottom left corners.
What is the initial y coordinate of the cen- ter of gravity of the dance floor and three couples?
Answer in units of m

Homework Equations



xcm: m1x1 + m2x2/m1+m2

The Attempt at a Solution


I am so lost any help would be appreciated! Thanks
 
Physics news on Phys.org
Hello Krobinson2851

Why don't you just apply the equation you have written down (and the equivalent one for yCM).
If you get stuck, show us what you've done.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top