# Infinite number of terms in the expansion (1+x)^n?

## Main Question or Discussion Point

hey,

I'm having a good deal of difficulty understanding why the following expansion has an infinite number of terms within it:

(1+x)n (|x|<1 where n is any real number)

Would someone mind explaining this to me please?

Thanks,
Oscar

hey,

I'm having a good deal of difficulty understanding why the following expansion has an infinite number of terms within it:

(1+x)n (|x|<1 where n is any real number)

Would someone mind explaining this to me please?

Thanks,
Oscar
If n was an integer there would be n terms, but how do you suppose someone expands $$(1+x)^\sqrt{2}$$?

I think he is referring to Newton's form of the binominal theorem for the absolute value of n less than 1.
Something like$$\sqrt{x+1}= x+\frac{1}{2x}-\frac{1}{8x^3}+-$$ In the case of x=5^2, we can expand like
$$\sqrt{5^2+1} = 5+1/10-1/1000+-+ =5 +99/1000 =5.099 +-+$$ This is sometimes a convient way to get rough answers mentally.

Last edited:
CRGreathouse