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## Homework Statement

d

^{2}y/dx

^{2}= 2-6x

Given: y(0)=-3 and y'(0)=4

## Homework Equations

None that I know of.

## The Attempt at a Solution

I know that for a single order derivative you would just find the integral, set y=1 and x=0. But I'm confused because here we're given two conditions, instead of just one. And I don't know how to do this type of problem with a second order derivative. But I know that:

The second integral of 2-6x is x

^{2}-x

^{3}. So,

y=x

^{2}-x

^{3}+ C

1= C

I also know that the first integral is 2x-3x

^{2}

But where does y'(0)=4 come into place? Do I need two equations here?

Mainly, I need to find the value of C, which stands for Constant.

Thanks! I'd really appreciate any help.