d2y/dx2 = 2-6x
Given: y(0)=-3 and y'(0)=4
None that I know of.
The Attempt at a Solution
I know that for a single order derivative you would just find the integral, set y=1 and x=0. But I'm confused because here we're given two conditions, instead of just one. And I don't know how to do this type of problem with a second order derivative. But I know that:
The second integral of 2-6x is x2-x3. So,
y=x2-x3 + C
I also know that the first integral is 2x-3x2
But where does y'(0)=4 come into place? Do I need two equations here?
Mainly, I need to find the value of C, which stands for Constant.
Thanks! I'd really appreciate any help.