Initial Velocity: Stone Released from Balloon

AI Thread Summary
When a stone is released from a balloon moving upwards at a constant velocity, its initial velocity is equal to that of the balloon, not opposite. The confusion arises from the assumption that the stone's velocity becomes zero immediately upon release. In reality, the stone continues to move upwards with the same velocity as the balloon at the moment of release. This concept is similar to throwing an object upwards from a moving hand, where the object retains the upward velocity of the hand. Understanding this principle clarifies the dynamics of objects in motion relative to their initial conditions.
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A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
 
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manimaran1605 said:
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

So you're saying that there's NO difference between just releasing the stone from a stationary balloon that isn't moving? Think again.

Zz.
 
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manimaran1605 said:
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how?
No, not opposite sign. Same sign.
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
You're free to think whatever you want. That doesn't make it right.
 
manimaran1605 said:
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

Think about that for a moment. When you throw a stone upwards, you release it from your hand while your hand is moving upwards rapidly... What happens?
 

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