Innner products and basis representation

iontail
Messages
22
Reaction score
0
hi, I have a quickon vector spaces.

Say for example we have


X = a1U1 + a2U2 ...anUn
this can be written as

X = sum of ( i=0 to n) ai Ui


now how can I get and expression of ai in therms of X and Ui.

do we use inner product to do this...ans someone please explain how to go forward.
 
Physics news on Phys.org
If the Ui basis is "orthonormal" then, taking the inner product of X with Uk gives <X, U_n]>= a_1 <U_1,U_k>+ \cdot\cdot\cdot+ a_k<U_k,U_k>+ \cdot\cdot\cdot+ a_n<U_n, U_k>= a_1(0)+ \cdot\cdot\cdot+ a_k(1)+ \cdot\cdot\cdot+ a_n(0)= a_k.

That is, for an orthonormal basis, a_k= <X, U_k>. If the basis is NOT orthonormal, there is no simple formula. That's why orthonormal bases are so popular!
 
the basis is orthonormal...so the solution you suggested should be ok...however i don't have latex and have never used it before so can't view your reply. do I just downlad latex to view the thread or do I have to do something else.
 
thanks for the reply...as well.
 
LaTeX

iontail said:
...however i don't have latex and have never used it before so can't view your reply. do I just downlad latex to view the thread or do I have to do something else.

Hi iontail! :smile:

You don't need to "have" LaTeX, it should be visible anyway.

There's just something wrong with that particular LaTeX …I can't read it either :rolleyes:

(I can't see what's wrong with the code though.)

To see the original code, just click on the REPLY button. :wink:
 
Here is what HallsofIvy want to write:

<X, U_n]>= a_1 <U_1,U_k>+ \cdot\cdot\cdot+ a_k<U_k,U_k>+ \cdot\cdot\cdot+ a_n<U_n, U_k>= a_1(0)+ \cdot\cdot\cdot+ a_k(1)+ \cdot\cdot\cdot+ a_n(0)= a_k
 
##\textbf{Exercise 10}:## I came across the following solution online: Questions: 1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##" 2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...
Back
Top