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Insertion Loss in a (T) Two Port Network

  1. Sep 29, 2013 #1
    1. The problem statement, all variables and given/known data

    Calculate the insertion loss for the network in the diagram?

    2. Relevant equations

    20log(N)dB

    N = R0 + R1 / R0 - R1

    3. The attempt at a solution


    N = R0 + R1 / R0 - R1

    N = 141.42 + 100 / 141.42 - 100

    N = 241.42 / 41.42

    N = 5.82858

    20log(5.82858) = 15.311

    Insertion Loss = 15.31 dB

    Can someone please confirm I am correct or incorrect?
     

    Attached Files:

  2. jcsd
  3. Dec 10, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    Looks good. You might use some parentheses to make the order of operations on your math clear :wink:

    You probably should have explained where the R0 value came from, although it can be derived from the filter circuit itself with the assumption that it is impedance matched to the source and sink impedances.
     
  4. Dec 10, 2013 #3
    INSLOSS.jpg

    R[itex]_0{}[/itex]=[itex]\sqrt{R^2{}_1{}+2R_{1}R_{2}}[/itex]

    I suppose by 'N' you mean I1/I2
     
    Last edited: Dec 10, 2013
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