Identifying Cations from Insoluble Precipitates - AgCl, Na2SO4 & More

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The discussion focuses on identifying cations from a colorless solution based on the formation of specific precipitates. The student correctly identifies precipitate A as AgCl, indicating the presence of Ag+. However, confusion arises regarding the subsequent addition of Na2SO4 and the resulting precipitate, with suggestions of insoluble sulfates and transition metal hydroxides for precipitates B and C. Participants emphasize the importance of solubility rules and clarify that certain cations, like lead, may not be present due to reactivity differences. Ultimately, the conversation highlights the need for a clear understanding of chemical reactions and solubility principles in identifying the cations.
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Homework Statement


A student was given a sample of a colourless solution containing three cations and was asked to identify the cations. The student carried out a series of reactions as shown in the flow chart below:

Screen Shot 2016-06-30 at 3.55.20 PM.png


From the information above, suggest three cations which could be in the sample and would form the precipitates A, B and C. Give the formula for each precipitate.

Homework Equations

The Attempt at a Solution



I think that precipitate A is AgCl because AgCl is insoluble. This means one of the cations is Ag+. However, I am stuck and don't really know how to move on. In the second step, Na2SO4 solution is added to the AgCl. I am not sure what precipitate will be formed. I am guessing that it has something to do with the other cations but I don't really know. I am pretty sure I have misinterpreted the question so could some please explain where I went wrong?

Cheers!
 
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You are right about AgCl.

What insoluble sulfates do you know? Hydroxides?

It is all about solubility rules.
 
Calcium sulfate, barium sulfate, lead sulfate, silver sulfate and strontium sulfate are all insoluble. So I guess any of these cations could be in the solution and they can be precipitate B.

Transition metal hydroxides are insoluble. So any transition metal hydroxide can be precipitate C.

I think I got confused and thought that the Na2SO4 was added to precipitate A and not the solution. Are these the answers you are expecting?

Thanks!
 
TT0 said:
Calcium sulfate, barium sulfate, lead sulfate, silver sulfate and strontium sulfate are all insoluble. So I guess any of these cations could be in the solution and they can be precipitate B.

Not bad, but not entirely correct either. One of these cations is for sure not present in the solution.

Transition metal hydroxides are insoluble. So any transition metal hydroxide can be precipitate C.

White, gelatinous. Compounds of transition metals are rarely colorless.
 
Not bad, but not entirely correct either. One of these cations is for sure not present in the solution.
I would say lead because I guess it is less reactive than silver so the precipitate formed will be Ag2SO4 and not PbSO4. But this isn't really a logical explanation I think.

White, gelatinous. Compounds of transition metals are rarely colorless.
I am not sure which transition metals produce colourless compounds. I am guessing the neutral element should be a silver colour so maybe zinc or iron?

Cheers!
 
TT0 said:
I would say lead because I guess it is less reactive than silver so the precipitate formed will be Ag2SO4 and not PbSO4. But this isn't really a logical explanation I think.

What was the very first step of the procedure?

Just try to google for "gelatinous white hydroxide".
 
What was the very first step of the procedure?

I see, the AgCl was already removed so no silver cations would be left. I misinterpreted the question. :(

Just try to google for "gelatinous white hydroxide".

Zinc and aluminium hydroxides form this. They also dissolve in excess NaOH. Why does this happen? The reaction for zinc is:

Zn2+ + 2NaOH ↔ Zn(OH)2 + 2Na+

If more NaOH is added, then the equilibrium will shift to the right so why does it dissolve again in excess NaOH?

Thanks!
 
I see thanks! So the answer I gave above is correct?
 
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Yes.
 
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