Instead, you should have divided by 3:R2=R2/3-R1/3

AI Thread Summary
The discussion revolves around a matrix manipulation where the user attempts to compute the determinant of a matrix through row operations. The user correctly performs several row operations but mistakenly multiplies the determinant by 3 when applying the operation R2=3R2-R1. This error leads to an incorrect determinant calculation of -45 instead of the correct -15. The community highlights the importance of tracking changes to the determinant during row operations to avoid such mistakes. The user is advised to adjust their calculations accordingly to arrive at the correct answer.
Airbus
Messages
1
Reaction score
0

Homework Statement


A = \left(\begin{array}{cccc}<br /> 3 &amp; 5 &amp; -2 &amp; 7\\<br /> 1 &amp; 2 &amp; -1 &amp; 1\\<br /> 2 &amp; 4 &amp; 1 &amp; 5\\<br /> 3 &amp; 7 &amp; 5 &amp; 3<br /> \end{array}<br /> \right)

Homework Equations


The Attempt at a Solution


R4=R4-R1
R3=R3-2R2
A = \left(\begin{array}{cccc}<br /> 3 &amp; 5 &amp; -2 &amp; 7\\<br /> 1 &amp; 2 &amp; -1 &amp; 1\\<br /> 0 &amp; 0 &amp; 3 &amp; 3\\<br /> 0 &amp; 2 &amp; 7 &amp; -4<br /> \end{array}<br /> \right)
R2=3R2-R1
A = \left(\begin{array}{cccc}<br /> 3 &amp; 5 &amp; -2 &amp; 7\\<br /> 0 &amp; 1 &amp; -1 &amp; 4\\<br /> 0 &amp; 0 &amp; 3 &amp; 3\\<br /> 0 &amp; 2 &amp; 7 &amp; -4<br /> \end{array}<br /> \right)
R4=R4-2R2
A = \left(\begin{array}{cccc}<br /> 3 &amp; 5 &amp; -2 &amp; 7\\<br /> 0 &amp; 1 &amp; -1 &amp; 4\\<br /> 0 &amp; 0 &amp; 3 &amp; 3\\<br /> 0 &amp; 0 &amp; 9 &amp; 4<br /> \end{array}<br /> \right)
R4=R4-3R3
A = \left(\begin{array}{cccc}<br /> 3 &amp; 5 &amp; -2 &amp; 7\\<br /> 0 &amp; 1 &amp; -1 &amp; 4\\<br /> 0 &amp; 0 &amp; 3 &amp; 3\\<br /> 0 &amp; 0 &amp; 0 &amp; -5<br /> \end{array}<br /> \right)

3*1*3*-5 = -45

but the ans. is -15

Can someone correct me?
Because I couldn't find any mistake

Thank you very much
 
Physics news on Phys.org
You multiplied the determinant by 3 when you did this operation:

R2=3R2-R1
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top