Integer Sequence: Solve & Generate Terms

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    Integer Sequence
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Homework Help Overview

The discussion revolves around identifying a formula or rule for generating terms in a specific integer sequence that begins with 2, 4, 16, 256, 65536, and explores the underlying pattern of the sequence.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between terms, with one noting that each term appears to be derived from multiplying the previous term by itself. Others suggest considering the exponents of 2 to find a clearer pattern.

Discussion Status

The conversation has progressed with participants exploring the nature of the sequence and suggesting potential formulas. There is an indication of understanding emerging, particularly with one participant proposing a formula based on the observed pattern.

Contextual Notes

Participants express a need for clarity and guidance in identifying the rule for the sequence, indicating some uncertainty about the approach to take for larger terms.

Madonna M.
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1. Homework Statement

Provide a simple formula or rule that generates the terms of an integer sequence that begins with :

* 2,4,16,256,65536,...


3. The Attempt at a Solution

I have tried a lot to solve it but i ended up with nothing,although i know that finding a term in the following sequence depends on multiplying the number by itself. For example if i want to get the 3rd term i will multiply the 2nd term by itself (4*4)=16 and same goes to the rest of the sequence,but what about if i want to get the 100th term,of course i won't multiply each term by itself until i reach the needed term,a formula or a rule would be more helpful.

Thanks in advance :)
 
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think about what exponents of 2 are needed to give that sequence.
 
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could you give me more clear clue please?? :)
 
Madonna M. said:
could you give me more clear clue please?? :)

Your sequence is ##2^1, 2^2, 2^4, 2^8, 2^{16}, ...##.
See the pattern?
 
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well,do you mean that every time am going to multiply the power of the previous term by 2 to get the next one?
 
Ahaa i got it thanks a lot,i think it would be 2^(2^(n-1))
 
Good! :)
 

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