Integral and Fundamental Theorem of Calculus

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Homework Help Overview

The discussion revolves around evaluating the definite integral of the function \(2 - x^2\) from 0 to 2, specifically using the definition of the definite integral and the Fundamental Theorem of Calculus (FTC).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the correct interpretation of the integral notation and clarify the limits of integration. There are attempts to express the integral in different forms and check the validity of the original poster's statement.

Discussion Status

Some participants have provided interpretations of the integral, and there is a recognition of the correct limits of integration. One participant has calculated the integral and shared the result, while another questions if the same result can be obtained using the FTC.

Contextual Notes

There is some confusion regarding the notation used in the original problem statement, leading to clarifications about the intended integral limits and function. The discussion reflects varying interpretations of the problem setup.

jkeatin
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Homework Statement


Find [tex]2 \int 0 \[/tex] (2-x^2)dx

using def of the definite integral and
using FTC


Homework Equations





The Attempt at a Solution


any help on how to start would be great?
 
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This looks really odd. Do you really mean [tex]2\int 0^{2-x^2} dx[/tex]?
 
naw.I think he means integral from 0 to 2 of 2-x^2..??
 
yeah camilus is right
 
am i gettin it close, lim n-->infinity {[8/n^3(i^2)] +4}
 
the answer is 4/3.

integral from 0 to 2 of 2-x^2 = [2x-(x^3)/3] evaluated at 2. You can ignore the zero.

2(2)-(2^3)/3 = 4 - 8/3 = (12 - 8)/3 = 4/3
 
oh i get ya, and using ftc id get the same answer just a different way correct?
 
thanks for the help camilus
 

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