Kinetica Messages 83 Reaction score 0 Thread starter Aug 3, 2010 #1 Homework Statement integral: x2 sqrt(2+x3) dx Homework Equations The Attempt at a Solution Should I use substitution? Should I do it as a power?
Homework Statement integral: x2 sqrt(2+x3) dx Homework Equations The Attempt at a Solution Should I use substitution? Should I do it as a power?
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Aug 4, 2010 #3 Since the only difficulty is that "[itex]2+ x^3[/itex]" inside the square root, let [itex]u= 2+ x^3[/itex] seems an obvious way to go.
Since the only difficulty is that "[itex]2+ x^3[/itex]" inside the square root, let [itex]u= 2+ x^3[/itex] seems an obvious way to go.
Kinetica Messages 83 Reaction score 0 Aug 4, 2010 #4 So when I substitute it as HallsofIvy suggested, what do I do with x2dx? x2dx=du? integral: sqrt(u)du=2u3/2/3... stuck.
So when I substitute it as HallsofIvy suggested, what do I do with x2dx? x2dx=du? integral: sqrt(u)du=2u3/2/3... stuck.
Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 Aug 4, 2010 #5 If u=2+x^3 isn't du=3*x^2*dx? Isn't that how substitution works?
Kinetica Messages 83 Reaction score 0 Aug 4, 2010 #6 I am extremely confused with the next step of the solution. integral sqrt(u)du/(3x2) is this the correct substitution?
I am extremely confused with the next step of the solution. integral sqrt(u)du/(3x2) is this the correct substitution?
Dick Science Advisor Homework Helper Messages 26,254 Reaction score 623 Aug 4, 2010 #7 Well, no. What happened to the x^2 in your original problem? Isn't it x^2*sqrt(u)*(du/(3*x^2))?