(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Sec(x)/((ln(tan(x)+sec(x))^1/2)

We were instructed to find the integral

2. Relevant equations

Here is a link to the wolfram solution, i dont understand the steps they took

http://www.wolframalpha.com/input/?i=Integral+of+Sec%28x%29%2F%28%28ln%28sec%28x%29%2Btan%28x%29%29^1%2F2%29%29

3. The attempt at a solution

I understand that using the substitution method using u = Ln(tan(x)+sec(x))

du = Sec(x)^2+tan(x)Sec(x)/Sec(x)+Tan(x) dx

I do not understand how to substitute this and get 1/((u)^1/2) which is according to wolfram, I dont understand how the substitution method eliminates the Sec from the numerator, Later they evaluate that 1/(u^(1/2)) as 2((u)^1/2) can someone please explain these intermediate steps?

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# Homework Help: Integral of Logarithms + Trig Functions

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