Evaluating Integrals of Exponential Functions with Dirac Delta

AI Thread Summary
The integral of the form ∫ d³x e^(i(k·x)) evaluates to (2π)³δ(r), where δ is the Dirac delta function. Participants discussed rewriting the exponential using Euler's formula and performing angular integration. Clarification was provided on whether "d" refers to a constant or a differential operator, confirming it represents the integration measure over three spatial dimensions. The conversation highlighted the importance of specifying the desired form of the result, particularly in terms of the Dirac delta function. Overall, the thread focused on techniques for evaluating integrals involving exponential functions and the Dirac delta function.
Dixanadu
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Hey guys,

if I have an integral of the form \int d^{3}x \hspace{2mm} e^{i(k\cdot x)}, how do I evaluate this?

Thanks a bunch...
 
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Is that d a constant, or the differential operator, or what?
 
its the integration of measure, over 3 spatial dimensions
 
Dixanadu said:
its the integration of measure, over 3 spatial dimensions
How can you rewrite the exponential? Maybe try using Euler's formula if you aren't confident with the exponential.
 
Write {\bf k\cdot x}=kx\cos\theta. Then do the angular integration.
 
Or in Cartesian coordinates, write out the dot product in terms of components: ##\vec k \cdot \vec x = k_x x + k_y y + k_z z##.
 
Dixanadu said:
Hey guys,

if I have an integral of the form \int d^{3}x \hspace{2mm} e^{i(k\cdot x)}, how do I evaluate this?
Thanks a bunch...
\int d^{3}x \hspace{2mm} e^{i(k\cdot x)}=(2\pi)^3\delta({\bf r}), the Dirac delta function.
 
Thank you Meir Achuz - that's what I was looking for :D thank you! Thanks everyone else for your help, I guess I should've specified that I was looking for it in terms of the Dirac delta.
 
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